The installation procedure of the FOSUserBundle is described in the main Symfony docs
You can:
LexikJWTAuthenticationBundle
If you are using the API Platform Standard Edition, you will need to enable the form services in the symfony framework configuration options:
# api/config/packages/framework.yaml
framework:
form: { enabled: true }
User
Entity with Serialization GroupsHere’s an example of declaration of a Doctrine ORM User class.
There’s also an example for a Doctrine MongoDB ODM.
You need to use serialization groups to hide some properties like plainPassword
(only in read) and password
. The properties
shown are handled with normalizationContext
, while the properties
you can modify are handled with denormalizationContext
.
Create your User entity with serialization groups:
<?php
// api/src/Entity/User.php
namespace App\Entity;
use ApiPlatform\Metadata\ApiResource;
use Doctrine\ORM\Mapping as ORM;
use FOS\UserBundle\Model\User as BaseUser;
use FOS\UserBundle\Model\UserInterface;
use Symfony\Component\Serializer\Annotation\Groups;
#[ORM\Entity]
#[ORM\Table(name: 'fos_user')]
#[ApiResource(
normalizationContext: ['groups' => ['user']],
denormalizationContext: ['groups' => ['user', 'user:write']],
)]
class User extends BaseUser
{
#[ORM\Id, ORM\Column, ORM\GeneratedValue]
protected ?int $id = null;
#[Groups("user")]
protected string $email;
#[ORM\Column(nullable: true)]
#[Groups("user")]
protected string $fullname;
#[Groups("user:write")]
protected string $plainPassword;
#[Groups("user")]
protected string $username;
public function setFullname(?string $fullname): void
{
$this->fullname = $fullname;
}
public function getFullname(): ?string
{
return $this->fullname;
}
public function isUser(?UserInterface $user = null): bool
{
return $user instanceof self && $user->id === $this->id;
}
}
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